document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32233>Question 32233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The value of a two-digit number is twice as large as the sum of its digits.  If the digits were reversed, the resulting number would be 9 less than 5 times the original number.  Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18761 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be ab<BR>\n" );
document.write( "It's \"value\" is 10a+b<BR>\n" );
document.write( "EQUATION#1:<BR>\n" );
document.write( "10a+b=2(a+b)<BR>\n" );
document.write( "8a=b<BR>\n" );
document.write( "If the digits are reversed the number is ba<BR>\n" );
document.write( "Then it's value is 10b+a<BR>\n" );
document.write( "EQUATION#2:<BR>\n" );
document.write( "10b+a+9=5(10a+b)<BR>\n" );
document.write( "5b+9=49a<BR>\n" );
document.write( "Make a substitutin for \"b\", using b=8a.<BR>\n" );
document.write( "the 5(8a)+9=49a<BR>\n" );
document.write( "a=1<BR>\n" );
document.write( "Substitute into b=8a to get b=8<BR>\n" );
document.write( "The original number is ab=18<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );