document.write( "Question 255286: the permiter of a rectangle is 200 inches. the length exceeds the widthe by 20 inches. find the length and width \n" ); document.write( "
Algebra.Com's Answer #187592 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "Let's represent the width as x and the length as x+20. Now we can set up an equation like this: \n" ); document.write( "x+x+(x+20)+(x+20)=200 combine like terms will give us: \n" ); document.write( "4x+40=200 Subtract 40 from both sides will be: \n" ); document.write( "4x=160 Divide both sides by 4 will result in: \n" ); document.write( "x=40 inches for the width and the length is: \n" ); document.write( "60 inches \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "Check out a new math book at \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |