document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255037>Question 255037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose that the distribution is bell shaped. if approximately 68% of the relative increase in stock price lie between .61% and .87%, then the approximate value of the standard deviation for the distribution is ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187563 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose that the distribution is bell shaped. if approximately 68% of the relative increase in stock price lie between .61% and .87%, then the approximate value of the standard deviation for the distribution is ?<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "68% lies within one standard deviation of the mean.<BR>\n" );
document.write( "So 0.87-0.61 = 0.26 is 2 standard deviations (one to the left<BR>\n" );
document.write( "and one to the right of the mean).<BR>\n" );
document.write( "--<BR>\n" );
document.write( "So one std is 0.26/2 = 0.13 or 13%<BR>\n" );
document.write( "=========================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );