document.write( "Question 255132: The credit score of a 35 year old applying for a mortgage is normally distributed with a mean of 600 abd a standard deviation of 100. \r
\n" ); document.write( "\n" ); document.write( "A) Find the credit score that defines the upper 5 percent.\r
\n" ); document.write( "\n" ); document.write( "B) Seventy- five percent of customers will have a credit score higher than what value?\r
\n" ); document.write( "\n" ); document.write( "C) In what range would the middle 80 percent of credit scores lie. \r
\n" ); document.write( "\n" ); document.write( "Please help! thanks
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Algebra.Com's Answer #187555 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The credit score of a 35 year old applying for a mortgage is normally distributed with a mean of 600 abd a standard deviation of 100.
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\n" ); document.write( "A) Find the credit score that defines the upper 5 percent.
\n" ); document.write( "The cutoff z-score is 1.645
\n" ); document.write( "Use x = zs+u to find the raw score.
\n" ); document.write( "x = 1.645*100+600
\n" ); document.write( "x = 164.5+600
\n" ); document.write( "x = 764.5
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\n" ); document.write( "B) Seventy- five percent of customers will have a credit score higher than what value?
\n" ); document.write( "That would be the left-tail cutoff for 25%:
\n" ); document.write( "That z is invNorm(0.25) = -0.6745
\n" ); document.write( "x = -0.6745*100+600
\n" ); document.write( "x = -67.45+600
\n" ); document.write( "x = 532.55
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\n" ); document.write( "C) In what range would the middle 80 percent of credit scores lie.
\n" ); document.write( "That is a left-tail cutoff at 10% and a right-tail cutoff at 90%
\n" ); document.write( "z = invNorm(0.10) = -1.2816 and z = +1.2816
\n" ); document.write( "I'll let you figure out the x values.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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