document.write( "Question 255272: For his art class, Bryce bought 2 kg of dark clay and 3 kg of light clay, paying $22 for the clay. He later needed 1 kg of dark clay and 2 kg of light clay,costing $13 altogether. How much more per kg does the the dark clay cost than the light clay, in dollars\r
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Algebra.Com's Answer #187539 by palanisamy(496)\"\" \"About 
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Let the cost of dark clay = $ x per kg
\n" ); document.write( "and the cost of light clay = $ y per kg
\n" ); document.write( "Bryce bought 2 kg of dark clay and 3 kg of light clay, paying $22 for the clay
\n" ); document.write( "So we have, 2x+3y = 22 ...(1)
\n" ); document.write( "Then he bought 1 kg of dark clay and 2 kg of light clay,costing $13
\n" ); document.write( " x+2y = 13 ...(2)
\n" ); document.write( "(2)*2 => 2x+4y = 26 ...(3)
\n" ); document.write( "(1)-(3)=> 3y-4y = 22-26
\n" ); document.write( " -y = -4
\n" ); document.write( " y = 4
\n" ); document.write( "Substituting in (1), we get, 2x+3*4 = 22
\n" ); document.write( " 2x = 22-12
\n" ); document.write( " 2x = 10
\n" ); document.write( " x = 10/2 = 5
\n" ); document.write( "Therefore, the cost of dark clay = $ 5 per kg
\n" ); document.write( "and the cost of light clay = $ 4 per kg
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