document.write( "Question 255219: Find the dimensions of a rectangle whose area is 180 square meters and whose perimeter is 54 meters. \n" ); document.write( "
Algebra.Com's Answer #187522 by palanisamy(496)\"\" \"About 
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Let the length of the rectangle = x
\n" ); document.write( "and the width of the rectangle = y
\n" ); document.write( "Given, perimeter 2(x+y) = 54 mts
\n" ); document.write( " x+y = 54/2
\n" ); document.write( " x+y = 27
\n" ); document.write( " y = 27-x ...(1)
\n" ); document.write( "Also, area xy = 180
\n" ); document.write( " x(27-x) = 180
\n" ); document.write( " 27x-x^2 = 180
\n" ); document.write( " -x^2+27x-180 = 0
\n" ); document.write( " x^2-27x+180 = 0
\n" ); document.write( " (x-15)(x-12)= 0
\n" ); document.write( " x = 15 and x = 12
\n" ); document.write( "Therefore, the length of the rectangle = 15 mts
\n" ); document.write( "and the width of the rectangle is y = 27-15 = 12 mts
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