document.write( "Question 255247: At the beginning of a bicycle ride for charity Roberto and Juana are 30 mi apart. If they leave at the same time and ride in the same direction, Roberto overtakes Juanna in 6 hrs. If they ride toward each other, they meet in 1 hr. What are their speed? \n" ); document.write( "
Algebra.Com's Answer #187518 by palanisamy(496)\"\" \"About 
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Let the speed of Juana =x
\n" ); document.write( "Let the speed of Roberto =y
\n" ); document.write( "The distance between them is 30miles.
\n" ); document.write( "If they leave at the same time and ride in the same direction, Roberto overtakes Juanna in 6 hrs
\n" ); document.write( " 6y-6x = 30
\n" ); document.write( " 6(y-x)= 30
\n" ); document.write( " y-x = 30/6
\n" ); document.write( " y-x = 5 ...(1)
\n" ); document.write( "If they ride toward each other, they meet in 1 hr.
\n" ); document.write( " 1*x+1*y = 30
\n" ); document.write( " x+y = 30 ...(2)
\n" ); document.write( "(1)+(2)=> 2y = 35
\n" ); document.write( " y = 35/2
\n" ); document.write( " y = 17.5 miles/hr
\n" ); document.write( "Substituting in (1), we get
\n" ); document.write( " 17.5-x = 5
\n" ); document.write( " 17.5-5 = x
\n" ); document.write( " 12.5 = x
\n" ); document.write( " x = 12.5 miles/hr
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