document.write( "Question 255156: please just help me with these two problems I am so confused... but so happy my dad found this website!! I graphed these twice and got a line and when I did it wrong I made my own V shape on the Y axis on purpose.
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document.write( "4. y=|-3x|\r
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document.write( "40. y=-|x-3|\r
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document.write( "I have way more problems but I'm hoping if a professional shows me how to do it that well... I might understand it or get how to do this for my other problems. Thanks again!! \n" );
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Algebra.Com's Answer #187475 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! 4). y=|-3x| \n" ); document.write( "40). y=-|x-3| \r \n" ); document.write( "\n" ); document.write( "Remember the definition of absolute value:\r \n" ); document.write( "\n" ); document.write( "|a| = a if a>=0 \n" ); document.write( "|a| = -a if a<0\r \n" ); document.write( "\n" ); document.write( "So for #4 above we have y = -3x when -3x >= 0 and y = -(-3x) = 3x when -3x < 0. Dividing both sides of these inequalities by -3 and reversing the sign of the inequalities (because we are dividing by a negative) we have -3x >= 0 if and only if x < 0. Similarly -3x < 0 if and only if x>=0.\r \n" ); document.write( "\n" ); document.write( "So we have:\r \n" ); document.write( "\n" ); document.write( "the line y = -3x when x <= 0 and \n" ); document.write( "the line y = 3x when x > 0\r \n" ); document.write( "\n" ); document.write( "These are two \"half\" iines which form a \"V\" with the low point at (0,0) and opening upward around the y-axis.\r \n" ); document.write( "\n" ); document.write( "#40 is very similar. The \"V\" is shifted to the right to the point (3,0) and opens downward.\r \n" ); document.write( "\n" ); document.write( "I hope this helps. \n" ); document.write( " \n" ); document.write( " |