document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32210>Question 32210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period (the time required for one complete swing) of a simple pendulum varies directly as the square root of its lenth.  If a pendulum 12 feet long has a period of 4 seconds, find the period of a pendulum 3 feet long. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18744 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4/SQRT12=X/SQRT3 OR X*SQRT12=4*SQRT3 OR SQUARING BOTH SIDES WE GET<BR>\n" );
document.write( "12X~2=48 OR X~2=48/12 OR X~2=4 OR X=2 SECONDS. </SPAN>\n" );
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