document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255123>Question 255123</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering how you turn a word problem into an algebra equation.<BR>\n" );
document.write( "ex1.1.) The total receipts for a basketball game are $1400 for 788 tickets sold. Adults paid $2.50 for admission and students paid $1.25. How many of each kind of tickets were sold?<BR>\n" );
document.write( "If x is how many of each kind of tickets were sold i was wondering how you put it in an equation.\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187427 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would not use x for how many of each kind.<BR>\n" );
document.write( "I would use a for number of adult tickets<BR>\n" );
document.write( "and s for student tickets<BR>\n" );
document.write( "What they really want is how many adult and how many student tickets since we know the total is 788.<BR>\n" );
document.write( "a+s=788<BR>\n" );
document.write( "s=788-a<BR>\n" );
document.write( "2.50a+1.25s=1400<BR>\n" );
document.write( "you can substitute 788-a for s<BR>\n" );
document.write( "2.50a+1.25(788-a)=1400<BR>\n" );
document.write( "Now we have one unknown in one equation<BR>\n" );
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