document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255103>Question 255103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (-3y^2+3y+8)/((y-3)(3y+1))=-(&#12310;3y&#12311;^2-3y-8)/((y-3)(3y+1)) is correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187413 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No the 3 does not get squared. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );