document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254903>Question 254903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a regular hexagon with sides of 3\"is inscribed in a circle find the segment formed by a side of the hexagon and the circle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187386 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The angle subtended by one segment is 360/6 = 60 degrees. The area of the triangle is 1/2 * 3 * 3 + sin 60 = 9/4 * sqrt 3 . The area of the sector of the circle is 1/6 (pi * 3^2) = 9/6 * pi<BR>\n" );
document.write( "So area of segment is sector minus triangle<BR>\n" );
document.write( "9(pi/6 - (sqrt 3)/4)= 9((3.14/6) - (1.732/4)) </SPAN>\n" );
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