document.write( "Question 254990: solve 3x=log(12)25 \n" ); document.write( "

Algebra.Com's Answer #187371 by Alan3354(69443) $\"\"$ $\"About$

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3x=log(12)25
\n" ); document.write( "If you mean
\n" ); document.write( " $\"3x+=+log%2812%2C25%29\"$
\n" ); document.write( "3x = log(25)/log(12)
\n" ); document.write( "x = log(25)/(3*log(12))
\n" ); document.write( "x = log(25)/log(12^3)
\n" ); document.write( "x = log(25)/log(1728)
\n" ); document.write( "x =~ 0.43179
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