document.write( "Question 255064: The sides of an equilateral triangle are shortened by 12 units,13 units and 14 units respectively and a right angled triangle is formed.Find the side of the equilateral triangle. \n" ); document.write( "
Algebra.Com's Answer #187365 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x = 17.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "17 - 14 = 3 \n" ); document.write( "17 - 13 = 4 \n" ); document.write( "17 - 12 = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "345 triangle is a right triangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve by use of pythatogrean formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a^2 + b^2 = c^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is the side of the equilateral triangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-12) = largest side which would be equal to c.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-13) = midsize side which would be equal to b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-14) = smallest side which would be equal to a.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a^2 + b^2 = c^2 becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-14)^2 + (x-13)^2 = (x-12)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this becomes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 28x + 196 + x^2 - 26x + 169 = x^2 - 24x + 144\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x^2 - 54x + 365 = x^2 - 24x + 144\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract x^2 from both sides of equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 54x + 365 = -24x + 144\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add 24x to both sides of equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 30x + 365 = 144\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 144 from both sides of equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 30x + 221 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor this quadratic equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-17) * (x-13) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this makes x = 17 or x = 13.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x can't be 13 because then one of the sides of the triangle will be 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x has to be 17.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x is 17, you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x-12 = 17-12 = 5 \n" ); document.write( "x-13 = 17-13 = 4 \n" ); document.write( "x-14 = 17-14 = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your 345 triangle which is a right triangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "side of the equilateral triangle is 17.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |