document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255028>Question 255028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm just wondering if it's possible to simplify this further or if I'm even on the right track...\r<BR>\n" );
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document.write( "3^x=15 (find x)\r<BR>\n" );
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document.write( ">x=log&#8323;15<BR>\n" );
document.write( ">x=log&#8323;(3x5)<BR>\n" );
document.write( ">x=log&#8323;3 + log&#8323;5<BR>\n" );
document.write( ">x= 1 + log&#8323;5\r<BR>\n" );
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document.write( "Thanks for your help :o) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187354 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Second line should be<BR>\n" );
document.write( "x log3 = log 15 giving<BR>\n" );
document.write( "x = log 15 / log 3 = 1.1770 / 0.4771<BR>\n" );
document.write( "I haven't got a calculator handy but it is 2. something which fits since x = 2 would give 3^2 = 9 and 3^3 = 27<BR>\n" );
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