document.write( "Question 244686: Dandy Candy Co. mixes candy that costs $9 per pound with candy that costs $6.50 per pound. How many pounds of each are needed to make a 3-pound box that costs $25? \n" ); document.write( "
Algebra.Com's Answer #187352 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! Dandy Candy Co. mixes candy that costs $9 per pound with candy that costs $6.50 per pound. How many pounds of each are needed to make a 3-pound box that costs $25? \n" ); document.write( "pounds candy A=x, pounds candy B=y\r \n" ); document.write( "\n" ); document.write( "9x+6.5y=25 \n" ); document.write( "x+y=3\r \n" ); document.write( "\n" ); document.write( "x+y=3, solve for y \n" ); document.write( "y=3-x\r \n" ); document.write( "\n" ); document.write( "plug into 9x+6.5y=25 and solve for x \n" ); document.write( "9x+6.5(3-x)=25 \n" ); document.write( "9x+19.5-6.5x=25 \n" ); document.write( "9x-6.5x=25-19.5 \n" ); document.write( "2.5x=5.5 \n" ); document.write( "x=5.5/2.5=55/25=11/5=2.2\r \n" ); document.write( "\n" ); document.write( "plug 2.2 into x+y=3 and solve for y \n" ); document.write( "2.2+y=3 \n" ); document.write( "y=3-2.2=0.8\r \n" ); document.write( "\n" ); document.write( "2.2 pounds candy A and 0.8 pounds candy B\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |