document.write( "Question 255051: A rectangle has an area of 120 sq. cm.. Its length and width are whole numbers. What are the possibilities for the two numbers? Which possibility gives the smallest perimeter? \n" ); document.write( "
Algebra.Com's Answer #187334 by CharlesG2(834)\"\" \"About 
You can put this solution on YOUR website!
A rectangle has an area of 120 sq. cm.. Its length and width are whole numbers. What are the possibilities for the two numbers? Which possibility gives the smallest perimeter?\r
\n" ); document.write( "\n" ); document.write( "find the factors of 120:
\n" ); document.write( "120=1*120
\n" ); document.write( "120=2*60
\n" ); document.write( "120=3*40
\n" ); document.write( "120=4*30
\n" ); document.write( "120=5*24
\n" ); document.write( "120=6*20
\n" ); document.write( "120=8*15
\n" ); document.write( "120=10*12\r
\n" ); document.write( "\n" ); document.write( "perimeter of a rectangle = 2*length + 2 * width = 2 * (length + width)\r
\n" ); document.write( "\n" ); document.write( "perimeters of above factorizations:
\n" ); document.write( "2*(1+120)=2*121=142
\n" ); document.write( "2*(2+60)=2*62=124
\n" ); document.write( "2*(3+40)=2*43=86
\n" ); document.write( "2*(4+30)=2*34=68
\n" ); document.write( "2*(5+24)=2*29=58
\n" ); document.write( "2*(6+20)=2*26=52
\n" ); document.write( "2*(8+15)=2*23=46
\n" ); document.write( "2*(10+12)=2*22=44\r
\n" ); document.write( "\n" ); document.write( "the largest factors, 10 and 12 give smallest perimeter which is 44
\n" ); document.write( " \n" ); document.write( "
\n" );