document.write( "Question 254943: the length of a rectangle is 5 cm more that twice the width. the perimeter of the rectangle is 34 cm. find the demensions of the rectangke. \n" ); document.write( "
Algebra.Com's Answer #187311 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+5 \n" ); document.write( "2L+2W=34 \n" ); document.write( "2(2W+5)+2W=34 \n" ); document.write( "4W+10+2W=34 \n" ); document.write( "6W=34-10 \n" ); document.write( "6W=24 \n" ); document.write( "W=24/6 \n" ); document.write( "W=4 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*4+5=8+5=13 ANS. FOR THE LENGTH \n" ); document.write( "PROOF: \n" ); document.write( "2*13+2*4=34 \n" ); document.write( "26+8=34 \n" ); document.write( "34=34 \n" ); document.write( " \n" ); document.write( " |