document.write( "Question 255004: a rectangle has a perimeter of 12.0 meters. The area of the rectangle is 61.0 percent of maximum area for a rectangle with this perimeter. What is the length of the shorter side? \n" ); document.write( "
Algebra.Com's Answer #187304 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a rectangle has a perimeter of 12.0 meters. \n" ); document.write( "The area of the rectangle is 61.0 percent of maximum area for a rectangle with this perimeter. \n" ); document.write( " What is the length of the shorter side? \n" ); document.write( ": \n" ); document.write( "Max area is when the rectangle is square, in this case 3*3 = 9 sq/m \n" ); document.write( ": \n" ); document.write( ".61 * 9 = 5.49 sq/m \n" ); document.write( ": \n" ); document.write( "Let L = length, x = the width \n" ); document.write( "2L + 2x = 12 \n" ); document.write( "Simplify \n" ); document.write( "L + x = 6 \n" ); document.write( "L = (6-x) \n" ); document.write( ": \n" ); document.write( "The area: \n" ); document.write( "x(6-x) = 5.49 \n" ); document.write( "6x - x^2 = 5.49 \n" ); document.write( "A quadratic equation \n" ); document.write( "-x^2 + 6x - 5.49 = 0 \n" ); document.write( "Solve this using the quadratic equation, you should get two solutions \n" ); document.write( "x = 4.87 \n" ); document.write( "x = 1.13 m is the shorter side \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this by finding the area \n" ); document.write( "4.87 * 1.13 = 5.50 ~ 5.49 \n" ); document.write( " |