document.write( "Question 254962: Can someone please help me divide the following. (6x^2 - 31x + 5) / (x - 5) and (x^3 + 2x^2 - 3x + 2) / (x +1) \n" ); document.write( "

Algebra.Com's Answer #187270 by drk(1908) $\"\"$ $\"About$

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Lets take the first equation first. We can apply synthetic division. It is easier:
\n" ); document.write( "6x^2 - 31x + 5) / (x - 5)
\n" ); document.write( "It looks like this:
\n" ); document.write( "5 l . . . . 6 . . . . . -31 . . . . . . 5
\n" ); document.write( " . . . . . . . . . . . . .30 . . . . . . . -5
\n" ); document.write( " . . . . . . 6 . . . . . .-1 . . . . . . r = 0
\n" ); document.write( "So, we get 6x-1 with no remainder
\n" ); document.write( "--
\n" ); document.write( "We apply the same approach to the second one to get
\n" ); document.write( "(x^3 + 2x^2 - 3x + 2) / (x + 1)
\n" ); document.write( "(-1) l . . . . . . 1 . . . . . .2 . . . . . -3 . . . . . .2
\n" ); document.write( " . . . . . . . . . . . . . . . . .-1 . . . . . -1 . . . . .4
\n" ); document.write( " . . . . . . . . . .1 . . . . . .1 . . . . . -4 . . . . . .6
\n" ); document.write( "So, we get 1x^2 + 1x - 4 + 6/(x+1) \n" ); document.write( "

\n" );