document.write( "Question 254976: okay i need help on this problem. I've tried different ways to solve it but i can't seem to the find the answer. I NEED help., PLEASE. Find the standard form of the equation of the line that passes through the point (-3, -5) and is parallel to the line 2x-3y=-6. \n" ); document.write( "
Algebra.Com's Answer #187261 by drk(1908)\"\" \"About 
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Here is the question:
\n" ); document.write( "(-3, -5) and is parallel to the line 2x-3y=-6.
\n" ); document.write( "step 1 - solve the equation for y.
\n" ); document.write( "\"2x+-+3y+=+6\"
\n" ); document.write( "\"-3y+=+-2x+%2B+6\"
\n" ); document.write( "\"y+=+%282%2F3%29x+-+2\"
\n" ); document.write( "step 2 - find the slope.
\n" ); document.write( "Since we have Y = mx + b, the slope is m = 2/3
\n" ); document.write( "step 3 - we want parallel. Parallel lines have the same slope so our parallel slope = 2/3
\n" ); document.write( "step 4 - using y = mx + b plug in known information to find the b
\n" ); document.write( "\"y+=+mx+%2B+b\"
\n" ); document.write( "\"-5+=+%28-3%29%282%2F3%29+%2B+b\"
\n" ); document.write( "\"-3+=+b\"
\n" ); document.write( "Step 5 - write the equation.
\n" ); document.write( "\"Y+=+mx+%2B+b\"
\n" ); document.write( "\"Y+=+%282%2F3%29x+-2\"
\n" ); document.write( "
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