document.write( "Question 254964: Factor out the greatest common factor. 16y^5 - 24y^4 - 40y^3 \n" ); document.write( "
Algebra.Com's Answer #187248 by richwmiller(17219)\"\" \"About 
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16y^5 - 24y^4 - 40y^3
\n" ); document.write( "start with 4y^3\r
\n" ); document.write( "\n" ); document.write( "4y^3(4y^2-6y-10)
\n" ); document.write( "We could have gone higher than 4
\n" ); document.write( "let's go 2
\n" ); document.write( "4y^3*2(2y^2-3y-5)
\n" ); document.write( "8y^3(2y^2-3y-5)
\n" ); document.write( "Now we get to the fun part
\n" ); document.write( "we want factors of 2*-5 that add to -3
\n" ); document.write( "and we have them
\n" ); document.write( "2y^2 +2y -5y-5
\n" ); document.write( "group them
\n" ); document.write( "2y(y+1) -5(y+1)
\n" ); document.write( "(2y-5)(y+1)\r
\n" ); document.write( "\n" ); document.write( "8y^3*(y+1)*(2y-5)
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