document.write( "Question 254957: If A can finish a job 50% faster than B and 20% faster than C, and together they can finish the job in 4 hours, how long would it take A to finish the job alone? \n" ); document.write( "
Algebra.Com's Answer #187242 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If A can finish a job 50% faster than B and 20% faster than C, and together they can finish the job in 4 hours, how long would it take A to finish the job alone? \n" ); document.write( ": \n" ); document.write( "If A can finish a job 50% faster than B and 20% faster than C, and together they can finish the job in 4 hours, how long would it take A to finish the job alone? \n" ); document.write( ": \n" ); document.write( "let t = time required by A alone \n" ); document.write( "then \n" ); document.write( "1.5t = time required by B \n" ); document.write( "and \n" ); document.write( "1.2 = time required by C \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by 6t, results \n" ); document.write( "6(4) + 4(4) + 5(4) = 6t \n" ); document.write( "24 + 16 + 20 = 6t \n" ); document.write( "60 = 6t \n" ); document.write( "t = \n" ); document.write( "t = 10 hrs for A \n" ); document.write( "1.5(10) = 15 hrs for B \n" ); document.write( "1.2(10) = 12 hrs for C \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution on a calc: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |