document.write( "Question 254957: If A can finish a job 50% faster than B and 20% faster than C, and together they can finish the job in 4 hours, how long would it take A to finish the job alone? \n" ); document.write( "
Algebra.Com's Answer #187242 by ankor@dixie-net.com(22740)\"\" \"About 
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If A can finish a job 50% faster than B and 20% faster than C, and together they can finish the job in 4 hours, how long would it take A to finish the job alone?
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\n" ); document.write( "If A can finish a job 50% faster than B and 20% faster than C, and together they can finish the job in 4 hours, how long would it take A to finish the job alone?
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\n" ); document.write( "let t = time required by A alone
\n" ); document.write( "then
\n" ); document.write( "1.5t = time required by B
\n" ); document.write( "and
\n" ); document.write( "1.2 = time required by C
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "\"4%2Ft\" + \"4%2F%281.5t%29\" + \"4%2F%281.2t%29\" = 1
\n" ); document.write( "Multiply equation by 6t, results
\n" ); document.write( "6(4) + 4(4) + 5(4) = 6t
\n" ); document.write( "24 + 16 + 20 = 6t
\n" ); document.write( "60 = 6t
\n" ); document.write( "t = \"60%2F6\"
\n" ); document.write( "t = 10 hrs for A
\n" ); document.write( "1.5(10) = 15 hrs for B
\n" ); document.write( "1.2(10) = 12 hrs for C
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\n" ); document.write( "Check solution on a calc:
\n" ); document.write( "\"4%2F10\" + \"4%2F15\" + \"4%2F12\" = 1\r
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