document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32185>Question 32185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2(x+4)+3x=2(x+3)+8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18723 by </B><A HREF=/tutors/aboutme.mpl?userid=LifeDeathnCandy><B>LifeDeathnCandy(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LifeDeathnCandy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(x+4)+3x=2(x+3)+8<BR>\n" );
document.write( "To solve this you would have to distribute the 2x first on the left side. <BR>\n" );
document.write( "So you would have: 2x+4x+3x=2(x+3)+8<BR>\n" );
document.write( "Then you would have to distribute the 2 on the right side. <BR>\n" );
document.write( "So you would have: 2x+4x+3x=2x+6+8<BR>\n" );
document.write( "Then you group the alike numbers together and you get: 9x=2x+14<BR>\n" );
document.write( "Then you subtract the 2x from the right side and the left side. So you are left with 7x=14<BR>\n" );
document.write( "Then you divide 14 by 7 and you get x=2 </SPAN>\n" );
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