document.write( "Question 32191This question is from textbook Elementray and Intermediate Algebra
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document.write( ": Suppose that a certain radioactive substance has a half-life of 50 years. If there are presently 7500 grams of the substance, how much will remain after 32 years? Express your answer to the nearest gram.\r
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document.write( "Please help me solve this equation. \n" );
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Algebra.Com's Answer #18722 by Fermat(136)![]() ![]() You can put this solution on YOUR website! The equation to use is, \n" ); document.write( "M=Mo.2^(-t/T) \n" ); document.write( "where \n" ); document.write( "Mo is the original mass \n" ); document.write( "T is the half-life period \n" ); document.write( "t is the time since the start of measuring \n" ); document.write( "M is the mass at time t \n" ); document.write( "You have, \n" ); document.write( "Mo = 7500 gms \n" ); document.write( "T = 50 yrs \n" ); document.write( "t = 32 yrs \n" ); document.write( "M = ? \n" ); document.write( "Using the half-life eqn, \n" ); document.write( "M = 7500*2^(-32/50) \n" ); document.write( "M = 7500*2^(-0.64) \n" ); document.write( "M = 7500*0.641713 \n" ); document.write( "M = 4812.85 \n" ); document.write( "M = 4813 gms \n" ); document.write( "============ \n" ); document.write( " |