document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254846>Question 254846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x = 1 + 2^p and  y = 1 + 2^-p  then express y in terms of a single fraction involving x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187165 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let 2^p =t\r<BR>\n" );
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document.write( "then 2^-p will be 1/t  (this assumption is just for ease of view)\r<BR>\n" );
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document.write( "so x=1+t => t=x-1\r<BR>\n" );
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document.write( "and y=1+ 1/t\r<BR>\n" );
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document.write( "substitute the value of t\r<BR>\n" );
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document.write( "so we get y= 1 + 1/(x-1)\r<BR>\n" );
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document.write( "so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=x%2F%28x-1%29 ALIGN=MIDDLE  ALT=\"y=x%2F%28x-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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