document.write( "Question 254708: A spice mixture is 25% thyme. How many grams of thyme must be added to make a 15 gram mixture that is 40% thyme? \n" ); document.write( "
Algebra.Com's Answer #187162 by ankor@dixie-net.com(22740)\"\" \"About 
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A spice mixture is 25% thyme.
\n" ); document.write( "How many grams of thyme must be added to make a 15 gram mixture that is 40% thyme?
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\n" ); document.write( "Let x = amt of pure thyme to be added
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\n" ); document.write( "The amt of 25% mixture = (15-x)
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\n" ); document.write( "An amt of thyme equation
\n" ); document.write( "1.0x + .25(15-x) = .40(15)
\n" ); document.write( "1x + 3.75 - .25x = 6
\n" ); document.write( "1x - .25x = 6 - 3.75
\n" ); document.write( ".75x = 2.25
\n" ); document.write( "x = \"2.25%2F.75\"
\n" ); document.write( "x = 3 grams of pure thyme required to be added to 12 gr of the 25% mixture
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\n" ); document.write( "You can check solution in original equation \n" ); document.write( "
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