document.write( "Question 254824: Jake gave Patti a 5-yard head start in a 100-yard dash and Jake lost by only 1/4
\n" );
document.write( "yard. In how many more yards, beyond 100 yards, would Jake have overtaken
\n" );
document.write( "Patti?\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #187147 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jake gave Patti a 5-yard head start in a 100-yard dash and Jake lost by only 1/4 \n" ); document.write( "yard. \n" ); document.write( "In how many more yards, beyond 100 yards, would Jake have overtaken \n" ); document.write( "Patti? \n" ); document.write( ": \n" ); document.write( "When P's at the 100 yd marker, P has ran 95 yds in the same time interval as J ran 99.75 yds \n" ); document.write( "Use this to establish the speed of each runner \n" ); document.write( ": \n" ); document.write( "Let d = distance beyond the 100 yd marker where J overtakes P \n" ); document.write( ": \n" ); document.write( "Write a time equation Time = dist/speed \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "99.75d = 95(d+.25) \n" ); document.write( ": \n" ); document.write( "99.75d = 95d + 23.75 \n" ); document.write( ": \n" ); document.write( "99.75d - 95d = 23.75 \n" ); document.write( ": \n" ); document.write( "4.75d = 23.75 \n" ); document.write( "d = \n" ); document.write( "d = 5 yds past the 100 yd maker, J catches P \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the times \n" ); document.write( "5/95 = .0526 \n" ); document.write( "5.25/99.75 = .0526; J ran 5 |