document.write( "Question 254824: Jake gave Patti a 5-yard head start in a 100-yard dash and Jake lost by only 1/4
\n" ); document.write( "yard. In how many more yards, beyond 100 yards, would Jake have overtaken
\n" ); document.write( "Patti?\r
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Algebra.Com's Answer #187147 by ankor@dixie-net.com(22740)\"\" \"About 
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Jake gave Patti a 5-yard head start in a 100-yard dash and Jake lost by only 1/4
\n" ); document.write( "yard.
\n" ); document.write( "In how many more yards, beyond 100 yards, would Jake have overtaken
\n" ); document.write( "Patti?
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\n" ); document.write( "When P's at the 100 yd marker, P has ran 95 yds in the same time interval as J ran 99.75 yds
\n" ); document.write( "Use this to establish the speed of each runner
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\n" ); document.write( "Let d = distance beyond the 100 yd marker where J overtakes P
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\n" ); document.write( "Write a time equation Time = dist/speed
\n" ); document.write( "\"d%2F95\" = \"%28d%2B.25%29%2F99.75\"
\n" ); document.write( "cross multiply
\n" ); document.write( "99.75d = 95(d+.25)
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\n" ); document.write( "99.75d = 95d + 23.75
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\n" ); document.write( "99.75d - 95d = 23.75
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\n" ); document.write( "4.75d = 23.75
\n" ); document.write( "d = \"23.75%2F4.75\"
\n" ); document.write( "d = 5 yds past the 100 yd maker, J catches P
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\n" ); document.write( "Confirm this by finding the times
\n" ); document.write( "5/95 = .0526
\n" ); document.write( "5.25/99.75 = .0526; J ran 5\"1%2F4\" yds in the same time P ran 5 yds
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