document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254830>Question 254830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x+3=2x+9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187127 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The plan is to get all x on the left and all numbers on the right<BR>\n" );
document.write( "let's get rid of the 3 on the left <BR>\n" );
document.write( "How? What would cancel out +3 ? -3  would make it zero so we subtract 3 from both sides or add -3 to both sides<BR>\n" );
document.write( "5x=2x+6<BR>\n" );
document.write( "Wait there are x on the right. If we add -2x to both sides we can cancel out the x on the right<BR>\n" );
document.write( "3x=6<BR>\n" );
document.write( "almost there<BR>\n" );
document.write( "we still have 3 on the left <BR>\n" );
document.write( "divide by 3 this time<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "all done  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );