document.write( "Question 254828: If a^2 – bc = 7, b^2 + ac = 7, c^2 + ab = 7, then determine the value of a^2 + b^2 + c^2. \n" ); document.write( "
Algebra.Com's Answer #187123 by vksarvepalli(154)\"\" \"About 
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a^2 – bc = 7-------- 1
\n" ); document.write( " b^2 + ac = 7-------- 2
\n" ); document.write( " c^2 + ab = 7-------- 3\r
\n" ); document.write( "\n" ); document.write( "equating 1 and 2
\n" ); document.write( " then 2 and 3
\n" ); document.write( " then 3 and 1\r
\n" ); document.write( "\n" ); document.write( "we get either a=b+c
\n" ); document.write( " or b=c=-a\r
\n" ); document.write( "\n" ); document.write( "but if b=c=-a the given equations will not satisfy\r
\n" ); document.write( "\n" ); document.write( "so a=b+c\r
\n" ); document.write( "\n" ); document.write( "now add the three equations 1,2 & 3\r
\n" ); document.write( "\n" ); document.write( "we get \"a%5E2%96bc%2Bc%5E2%2Bab%2Bb%5E2%2Bac=21\"
\n" ); document.write( "=> \"a%5E2%2Bb%5E2%2Bc%5E2=21%2Bbc-a%28b%2Bc%29\"\r
\n" ); document.write( "\n" ); document.write( "but since b+c=a\r
\n" ); document.write( "\n" ); document.write( "we get \"a%5E2%2Bb%5E2%2Bc%5E2=21%2Bbc-a%5E2\"\r
\n" ); document.write( "\n" ); document.write( "from eq. 1 bc-a^2=-7\r
\n" ); document.write( "\n" ); document.write( "substituting this in above eq \r
\n" ); document.write( "\n" ); document.write( "we get \"a%5E2%2Bb%5E2%2Bc%5E2=21-7\"\r
\n" ); document.write( "\n" ); document.write( "so \"a%5E2%2Bb%5E2%2Bc%5E2=14\" Ans.\r
\n" ); document.write( "\n" ); document.write( "ans. a^2+b^2+c^2=14
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