document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254777>Question 254777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the dimensions of a rectangle that has a perimeter of 56 and an area of 96?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187121 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a and b be the two sides of a rectangle<BR>\n" );
document.write( "Then perimeter 2(a+b) = 56<BR>\n" );
document.write( "                 (a+b) =28  ..(1)<BR>\n" );
document.write( "Area             ab = 96    ...(2)<BR>\n" );
document.write( "Next, (a-b)^2 = (a+b)^2-4ab<BR>\n" );
document.write( "              =(28)^2-4*(96)<BR>\n" );
document.write( "              = 784-384<BR>\n" );
document.write( "      (a-b)^2 = 400<BR>\n" );
document.write( "          a-b = 20   ...(3)<BR>\n" );
document.write( "(1)+(3)=>  2a = 28+20<BR>\n" );
document.write( "           2a = 48<BR>\n" );
document.write( "            a = 24<BR>\n" );
document.write( "Substituting in (1),<BR>\n" );
document.write( "          24+b = 28<BR>\n" );
document.write( "             b = 28-24<BR>\n" );
document.write( "             b = 4<BR>\n" );
document.write( "Therefore the sides are 24 and 4 <BR>\n" );
document.write( "     </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );