document.write( "Question 254819: How do I go about this question? \r
\n" ); document.write( "\n" ); document.write( "Find the value of x for:\r
\n" ); document.write( "\n" ); document.write( "log2(x2 + 4x + 3) – log 2(x2 + x) = 4
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Algebra.Com's Answer #187105 by palanisamy(496)\"\" \"About 
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Given, log2(x2 + 4x + 3) – log 2(x2 + x) = 4
\n" ); document.write( " log2[(x^2+4x+3)/(x^2+x)] = 4
\n" ); document.write( "Taking anti-log, we get
\n" ); document.write( " [(x^2+4x+3)/(x^2+x)] =2^4
\n" ); document.write( " x^2+4x+3 = 16(x^2+x)
\n" ); document.write( " x^2+4x+3 = 16x^2+16x
\n" ); document.write( " 0 = 15x^2+12x-3
\n" ); document.write( "Dividing by 3, we get
\n" ); document.write( " 5x^2+4x-1 = 0
\n" ); document.write( " (5x-1)(x+1)=0
\n" ); document.write( " x = -1,1/5
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