document.write( "Question 254759: What does x= ?
\n" ); document.write( "2log base5(4x+1)=7
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Algebra.Com's Answer #187088 by edjones(8007)\"\" \"About 
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2log[5](4x+1)=7
\n" ); document.write( "log[5](4x+1)=7/2
\n" ); document.write( "5^(log[5](4x+1))=5^(7/2)
\n" ); document.write( "4x+1=125sqrt(5)
\n" ); document.write( "4x=125sqrt(5)-1
\n" ); document.write( "x=(125sqrt(5)-1)/4
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\n" ); document.write( "Ed
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