document.write( "Question 254746: What is the solution to (25x^2)-(16y^2)=400 ? \n" ); document.write( "
Algebra.Com's Answer #187069 by dabanfield(803)\"\" \"About 
You can put this solution on YOUR website!
(25x^2)-(16y^2)=400 ?\r
\n" ); document.write( "\n" ); document.write( "Divide by sides of the equation by 400: \r
\n" ); document.write( "\n" ); document.write( "25x^2/400 -16y^2/400 = 1\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "x^2/(400/25) - y^2/(400/16) = 1\r
\n" ); document.write( "\n" ); document.write( "This is in the standard form of a hyperbola [x^2/a^2 - y^2/b^2 = 1] which intersects the x-axis at (20/5,0) and (-20/5,0).\r
\n" ); document.write( "\n" ); document.write( "There are two asymtotes: y = (400/16)/(400/25)*x and y = -(400/16)/(400/25)*x \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );