document.write( "Question 254720: A soccer ball is kicked into the air and its height in meters above ground, h, recorded after t seconds. The height of the ball is described by the function h(t)= -3t^2+24t+1.
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document.write( "a) Determine when the ball reached its maximum height. (I think 1 sec)
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document.write( "b) Determine the ball's maximum height.
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document.write( "c) Determine the instantanneous velocity of the projectile at t= 2.8 sec.
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document.write( "d) Determine the instantaneous velocity of the projectile at t= 4.5 sec.What does the negative sign mean? ( That is is falling back to the ground?)
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document.write( "e) Determine the instantaneous velocity of the projectile at t=4 sec. \n" );
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Algebra.Com's Answer #187068 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A soccer ball is kicked into the air and its height in meters above ground, h, recorded after t seconds. The height of the ball is described by the function h(t)= -3t^2+24t+1. \n" ); document.write( "a) Determine when the ball reached its maximum height. (I think 1 sec) \n" ); document.write( "Max height is at the vertex of the parabola. \n" ); document.write( "at t = -b/2a \n" ); document.write( "t = -24/-6 = 4 seconds \n" ); document.write( "------------------ \n" ); document.write( "b) Determine the ball's maximum height. \n" ); document.write( "h(4) = -3*16 + 96 + 1 \n" ); document.write( "h(4) = 49 meters \n" ); document.write( "------------------------- \n" ); document.write( "c) Determine the instantaneous velocity of the projectile at t= 2.8 sec. \n" ); document.write( "h'(t) = -6t + 24 \n" ); document.write( "h'(2.8) = -16.8 + 24 \n" ); document.write( "h'(2.8) = 7.2 meters/sec (positive, going up) \n" ); document.write( "-------------------------- \n" ); document.write( "d) Determine the instantaneous velocity of the projectile at t= 4.5 sec.What does the negative sign mean? ( That is is falling back to the ground?) \n" ); document.write( "h'(4.5) = -6*4.5 + 24 \n" ); document.write( "h'(4.5) = -3 meters/second (negative --> going back down) \n" ); document.write( "-------------------------- \n" ); document.write( "e) Determine the instantaneous velocity of the projectile at t=4 sec. \n" ); document.write( "h'(4) = -6*4 + 24 = 0 (it stops going up, and starts back down) \n" ); document.write( "--------------------------- \n" ); document.write( "h' is the 1st derivative of height with respect to time. I don't know how to do this without derivatives. \n" ); document.write( " \n" ); document.write( " |