document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254716>Question 254716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 63 ft squared.  the length is 2 ft longer than the width.  what are the dimentions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187036 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let W = width and L = length.<BR>\n" );
document.write( "the length is 2 ft longer than the width translates into<BR>\n" );
document.write( "L = W + 2<BR>\n" );
document.write( "A = L x W<BR>\n" );
document.write( "A = (W+2)*W = 63<BR>\n" );
document.write( "We can see by inspection that W = 7 and W+2 = 9 = L, but I will go through the process any way.<BR>\n" );
document.write( "w^2 + 2W = 63<BR>\n" );
document.write( "W^2 + 2W - 63 = 0<BR>\n" );
document.write( "(W+9)(W-7) = 0<BR>\n" );
document.write( "W = -9 which is not possible<BR>\n" );
document.write( "W = 7.<BR>\n" );
document.write( "If W = 7, then L = 9. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );