document.write( "Question 32169This question is from textbook Strategies for problem solving
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document.write( ": The latent heat of fusion for ice is 79.8 cal/gram. how much ice can we melt with 1000 calories of heat? (Q=mlf) \n" );
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Algebra.Com's Answer #18703 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! THE FORMULA IS \n" ); document.write( "Q=ML...WHEN CHANGE OF STATE OCCURS AT CONSTANT TEMPERATURE...AND Q=MST...WHEN CHANGE IN TEMPERATURE OCCURS WITH NO CHANGE IN STATE..SO WE USE Q=ML HERE. \n" ); document.write( "1000=79.8*M \n" ); document.write( "M=1000/79.8=12.5 GMS APPROXIMATELY \n" ); document.write( " |