document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32170>Question 32170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Goodevening, please i cannot work out with your answer. I beg you again please answer me clearly \r<BR>\n" );
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document.write( "    In a 30,60 right triangle, if the opposite side of right angle is 6 units, find the area of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18702 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET US TAKE  ABC AS THE TRIANGLE WITH <BR>\n" );
document.write( "ANGLE A =60<BR>\n" );
document.write( "ANGLE B=90<BR>\n" );
document.write( "ANGLE C=30<BR>\n" );
document.write( "AC=6 UNITS<BR>\n" );
document.write( "IF YOU KNOW TRIGNOMETRY<BR>\n" );
document.write( "COS A = COS 60 =0.5=AB/AC=BC/6...OR...AB=6*0.5=3<BR>\n" );
document.write( "SIN A = SIN 60 =0.866=BC/AC=BC/6...OR..BC=6*0.866=5.196=5.2 SAY<BR>\n" );
document.write( "AREA  =0.5*AB*BC=0.5*3*5.2=7.8 SQ.UNITS. </SPAN>\n" );
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