document.write( "Question 254481: the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #187011 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+19 \n" ); document.write( "2L+2W=70 \n" ); document.write( "2(W+19)+2W=70 \n" ); document.write( "2W+38+2W=70 \n" ); document.write( "4W=70-38 \n" ); document.write( "4W=32 \n" ); document.write( "W=32/4 \n" ); document.write( "W=8 ANS. FOR THE WIDTH. \n" ); document.write( "L=8+19=27 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*27+2*8=70 \n" ); document.write( "54+16=70 \n" ); document.write( "70=70 \n" ); document.write( " \n" ); document.write( " |