document.write( "Question 254481: the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #187011 by checkley77(12844)\"\" \"About 
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L=W+19
\n" ); document.write( "2L+2W=70
\n" ); document.write( "2(W+19)+2W=70
\n" ); document.write( "2W+38+2W=70
\n" ); document.write( "4W=70-38
\n" ); document.write( "4W=32
\n" ); document.write( "W=32/4
\n" ); document.write( "W=8 ANS. FOR THE WIDTH.
\n" ); document.write( "L=8+19=27 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*27+2*8=70
\n" ); document.write( "54+16=70
\n" ); document.write( "70=70
\n" ); document.write( "
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