document.write( "Question 254605: Fine two numbers which add to 48 such that twice the smaller number is 6 more than the larger number. \n" ); document.write( "

Algebra.Com's Answer #186965 by drk(1908) $\"\"$ $\"About$

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Let x be smaller number and y = larger number
\n" ); document.write( "We have
\n" ); document.write( "(i) $\"x+%2B+y+=+48\"$
\n" ); document.write( "(ii) $\"2y+=+x+%2B+6\"$
\n" ); document.write( "Solve (i) for x to get
\n" ); document.write( "(iii) $\"x+=+48+-+y\"$
\n" ); document.write( "By substitution, we get
\n" ); document.write( "(iv) 2y = 48-y + 6}}}
\n" ); document.write( "and then
\n" ); document.write( " $\"3y+=+54\"$
\n" ); document.write( " $\"y+=+18\"$
\n" ); document.write( "Now, we find x as
\n" ); document.write( " $\"x+=+30\"$ \n" ); document.write( "

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