document.write( "Question 254632: Please help me solve this and can you show me how you did it? To rectangles are similar. The ratio of their corresponding sides is 1:4. Find the ratio of there perimeters and their areas \n" ); document.write( "
Algebra.Com's Answer #186959 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the ratio of the corresponding sides is 1:4, then if the measure of the length of the smaller rectangle is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter of the small rectangle is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and the perimeter of the large rectangle is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From the last relationship, factor out a 4:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that the quantity inside the parentheses is identical to the RHS of the first equation, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the ratio of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area of the smaller rectangle is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area of the larger rectangle is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ratio is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |