document.write( "Question 254600: the withd of a rectangle is 3cm more than half the length. the perimeter is 96cm. what is the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #186956 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! W=L/2+3 \n" ); document.write( "2W+2L=96 \n" ); document.write( "2(L/2+3)+2L=96 \n" ); document.write( "L+6+2L=96 \n" ); document.write( "3L=96-6 \n" ); document.write( "3L=90 \n" ); document.write( "L=90/3 \n" ); document.write( "L=30 ANS. FOR THE LENGTH. \n" ); document.write( "W=30/2+3 \n" ); document.write( "W=15+3=18 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*18+2*30=96 \n" ); document.write( "36+60=96 \n" ); document.write( "96=96 \n" ); document.write( " |