document.write( "Question 254587: order of operation for (3/4-2/3)+(1/2+1/3)\r
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document.write( "order of operation for 1/2+(2/3 div by 3/4)-(4/5*5/6) \n" );
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Algebra.Com's Answer #186914 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! order of operations \n" ); document.write( "PEMDAS \n" ); document.write( "parentheses \n" ); document.write( "exponents \n" ); document.write( "multiplication \n" ); document.write( "division \n" ); document.write( "addition \n" ); document.write( "subtraction \n" ); document.write( "Simplify and combine what is inside each set of the parentheses first \n" ); document.write( "then everything else will look simple. \n" ); document.write( "so start with the first set of parentheses \n" ); document.write( "(3/4-2/3)+(1/2+1/3)\r \n" ); document.write( "\n" ); document.write( " 1/2+(2/3 div by 3/4)-(4/5*5/6) \n" ); document.write( "you have to subtract fractions that don't have the same denominator.\r \n" ); document.write( "\n" ); document.write( "(3/4-2/3) \n" ); document.write( "for the first two you have denominators of 3 and 4 so you need 12ths\r \n" ); document.write( "\n" ); document.write( "(1/2+1/3) here you have denominators of 2 and 3 so need 6 but you will be adding to 12th's so it might be better to use 12th's here too\r \n" ); document.write( "\n" ); document.write( "second problem\r \n" ); document.write( "\n" ); document.write( " 1/2+(2/3 div by 3/4)-(4/5*5/6)\r \n" ); document.write( "\n" ); document.write( "First thing is divide one fraction by another. \n" ); document.write( "Do you remember the trick for that? \n" ); document.write( "take the second fraction and invert it (turn it upside down ) so now you have 3/4 turned over to 4/3 \n" ); document.write( "so now you multiply 2/3*4/3 which is the same as 2/3/3/4 and easier to deal with\r \n" ); document.write( "\n" ); document.write( "next you have to multiply 4/5*5/6 that is simple enough you get to cancel out a couple numbers here and reduce it\r \n" ); document.write( "\n" ); document.write( "now rewrite the fractions with the new results and see what you have. \n" ); document.write( "It should all look easy now. \n" ); document.write( "Let me know how you do \n" ); document.write( " |