document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254390>Question 254390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you write an equation that relates the monthly charge c, in dollars, to the number of kilowatt-hours used in amonth, 0 < x < 850 for the following word problem:\r<BR>\n" );
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document.write( "Mason power company supplies electricity to residential customer for a monthly customer charge of $7.25 plus 6.676 cents per kilowwat-hour for up to 850 kilowatt-hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186898 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mason power company supplies electricity to residential customer for a monthly customer charge of $7.25 plus 6.676 cents per kilowatt-hour for up to 850 kilowatt-hours?<BR>\n" );
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document.write( "c = .06676h + 7.25 (change cents to dollars)<BR>\n" );
document.write( "where<BR>\n" );
document.write( "h = is the no. of kwh up to 850 </SPAN>\n" );
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