document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254550>Question 254550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many sides does a polygon have if thhe sum of its interior angles is 540? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186879 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many sides does a polygon have if thhe sum of its interior angles is 540?\r<BR>\n" );
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document.write( "We have a formula for the sum of the intrior angles of a ploygon. \r<BR>\n" );
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document.write( "Where N is the number of sides of the polygon the sum of the angles then is (n-2)* 180.\r<BR>\n" );
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document.write( "In this case then:\r<BR>\n" );
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document.write( "(N-2)* 180 = 540<BR>\n" );
document.write( "180*N - 360 = 540<BR>\n" );
document.write( "180*N = 540+180 = 720<BR>\n" );
document.write( "N = 720/180 = 4 </SPAN>\n" );
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