document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254370>Question 254370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the substitution method to solve the linear system given. Express<BR>\n" );
document.write( "    the answer as an ordered pair of the form (x,y)<BR>\n" );
document.write( "     x + y = 5<BR>\n" );
document.write( "    2x + y = 6<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186807 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y = 5 or y=5-x<BR>\n" );
document.write( "2x + y = 6<BR>\n" );
document.write( "Now replace y in the second equation with (5-x) & solve for x.<BR>\n" );
document.write( "2x+(5-x)=6<BR>\n" );
document.write( "2x+5-x=6<BR>\n" );
document.write( "x=6-5<BR>\n" );
document.write( "x=1 ans.<BR>\n" );
document.write( "y=5-1<BR>\n" );
document.write( "y=4 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*1+4=6<BR>\n" );
document.write( "2+4=6<BR>\n" );
document.write( "6=6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );