document.write( "Question 254408: A chemist needs to mix a solution that is 34% silver nitrate with one that is 4% silver nitrate to obtain 100 milliliters of a mixture that is 7% silver nitrate. How many milliliter of each of the solutions must be used? \n" ); document.write( "
Algebra.Com's Answer #186795 by ankor@dixie-net.com(22740)\"\" \"About 
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A chemist needs to mix a solution that is 34% silver nitrate with one that is 4% silver nitrate to obtain 100 milliliters of a mixture that is 7% silver nitrate.
\n" ); document.write( "How many milliliter of each of the solutions must be used?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 34% solution required
\n" ); document.write( "It states that the resulting amt is to be 100 ml, therefore
\n" ); document.write( "(100-x) = amt 4% solution
\n" ); document.write( ":
\n" ); document.write( "Write an \"amt of silver nitrate\" equation
\n" ); document.write( ".34x + .04(100-x) = .07(100)
\n" ); document.write( ":
\n" ); document.write( ".34x + 4 - .04x = 7
\n" ); document.write( ".34x - .04x = 7 - 4
\n" ); document.write( ".3x = 3
\n" ); document.write( "x = \"3%2F.3\"
\n" ); document.write( "x = 10 ml of 34% solution
\n" ); document.write( "and
\n" ); document.write( "100 - 10 = 90 ml of 4% solution
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution:
\n" ); document.write( ".34(10) + .04(90) = .07(100)
\n" ); document.write( "3.4 + 3.6 = 7
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