document.write( "Question 254415: a charter company will provide a plane for a fare of $200 each for 80 or fewer passengers. For each passenger in excess of 80, the fare decreases $2 per person for everyone. What number of passengers would produce for the greatest revenue for the company?\r
\n" ); document.write( "\n" ); document.write( "That is question I need to solve, but what I really need is an equation to use to solve this.
\n" ); document.write( "If so, can you show me how to do step by step?
\n" ); document.write( "

Algebra.Com's Answer #186787 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
P = (80+x)(200-2x)
\n" ); document.write( "P = is a parabola that opens down. This means there is a maximum profit somewhere.
\n" ); document.write( "P = -2x^2 + 40x + 16000
\n" ); document.write( "We can find the vertex using -b/2a as
\n" ); document.write( "-b/2a = (-40/-4) = 10
\n" ); document.write( "Put in x = 10 and we get
\n" ); document.write( "P = 90*180 = 16200
\n" ); document.write( "Since the number of passengers increases, we get 80+10 = 90.\r
\n" ); document.write( "\n" ); document.write( "90 passengers gives us a profit of $16,200
\n" ); document.write( "
\n" );