document.write( "Question 254433: log(4-x)=log(x+8)+log(2x+13) \n" ); document.write( "
Algebra.Com's Answer #186753 by palanisamy(496)\"\" \"About 
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The given equation is
\n" ); document.write( " log(4-x)=log(x+8)+log(2x+13)
\n" ); document.write( " log(4-x) = log(x+8)(2x+13)
\n" ); document.write( "Taking anti-log,
\n" ); document.write( " (4-x) = (x+8)(2x+13)
\n" ); document.write( " 4-x = 2x^2+13x+16x+104
\n" ); document.write( " 0 = 2x^2+29x+104+x-4
\n" ); document.write( " 0 = 2x^2+30x+100
\n" ); document.write( "Dividing by 2,we get
\n" ); document.write( " x^2+15x+50 = 0
\n" ); document.write( " (x+5)(x+10) = 0
\n" ); document.write( " x = -5 or -10
\n" ); document.write( " \n" ); document.write( "
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