document.write( "Question 254441: Please help. I've been trying to solve this problem: Find two consecutive odd integers whose sum is 2 less than twice the larger. my working equation is: (x)+(x+2)=2(x+2)-2 (x is an odd integer; x+2 is the larger integer). All I get is 0! There must be something wrong with what I'm doing. Please help. Thanks! \n" ); document.write( "
Algebra.Com's Answer #186750 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
x+x+2=2(x+2)-2
\n" ); document.write( "2x+2=2x+4-2
\n" ); document.write( "2x=2x
\n" ); document.write( "x=1 or zero\r
\n" ); document.write( "\n" ); document.write( "check 1
\n" ); document.write( "1+3=2(3)-2
\n" ); document.write( "4=6-2
\n" ); document.write( "4=4
\n" ); document.write( "ok
\n" ); document.write( "Integers are 1 and 3\r
\n" ); document.write( "\n" ); document.write( "Another way to guarantee only odd answers for the variable is make the variable 2n+1 and 2n+3
\n" ); document.write( "2n+1+2n+3=2(2n+3)-2
\n" ); document.write( "4n+4=4n+6-2
\n" ); document.write( "4n=4n
\n" ); document.write( "n=0 or 1
\n" ); document.write( "odd must be 2n+1
\n" ); document.write( "2*0+1=1
\n" ); document.write( "check
\n" ); document.write( "1+3=2*3-2
\n" ); document.write( "4=4
\n" ); document.write( "ok
\n" ); document.write( "2*1+1=3\r
\n" ); document.write( "\n" ); document.write( "check
\n" ); document.write( "3+5=2(5)-2
\n" ); document.write( "8=8
\n" ); document.write( "ok
\n" ); document.write( "So this way we get pairs (1 and 3) and (3 and 5)\r
\n" ); document.write( "\n" ); document.write( "But I think ALL odd numbers fit the criteria
\n" ); document.write( "23 +25=2(25)-2
\n" ); document.write( "48=50-2
\n" ); document.write( " \n" ); document.write( "
\n" );